Unit Coversion

Unit conversion is a fundamental skill in mathematics and sciences that involves changing a quantity expressed in one unit to another unit without changing the value of the quantity. Understanding when to multiply and when to divide is crucial for accurate conversions. Let's go through the basics: 

Understanding and applying unit conversions is crucial for several reasons:

Unit conversion is more than just a mathematical exercise; it is a critical tool that ensures consistency, safety, and accuracy across various professional and everyday contexts. By studying unit conversions, individuals are better prepared to handle practical tasks efficiently and accurately.

Understanding Units and Conversion Factors

A conversion factor is a ratio or fraction representing the relationship between two different units. The conversion factor enables you to convert a quantity from one unit to another. This factor is derived from the equivalence between the two units. For example, we know that 1 inch equals 2.54 centimeters.  Thus, the conversion factor can be either 1 inch/2.54 cm  or 2.54 cm/1 inch,  depending on the conversion direction. 

When to Multiply

You multiply when you want to convert from a larger unit to a smaller unit. In this case, since you're converting to a smaller unit, you need more of them to represent the same amount.

See example below.

To simplify unit conversions so that you always multiply by the conversion factor, the key is to consistently set up your conversion so that the units you want to convert from cancel out, leaving only the units you want to convert to. This method involves always using the conversion factor as a fraction where the numerator is the unit you're converting to, and the denominator is the unit you're converting from. 

Basic Principle

Whenever you're faced with a unit conversion, write the conversion factor as a fraction that will cancel out the initial unit and leave you with the desired unit. Always multiply by this fraction.

Example 1: Feet to Inches 

Conversion: 12 in = 1 ft

Conversion Factor: 12in/1ft or 1ft/12in


Question: Convert 5 feet to inches.
Process:  5 ft ×(12in/1ft) = 60 in. We are using the 12in/1ft conversion factor here since we want to cancel out feet. 

To ensure that unit conversions are performed correctly, we choose the conversion factor so that the unit we are starting with (our original unit) is placed in the denominator of the conversion factor. This setup allows the original unit to cancel out when we multiply, leaving us with the desired unit in the numerator. By structuring the conversion factor, we effectively eliminate and convert the original unit into the new unit we need. This method simplifies the process and guarantees that the units are correctly converted by always allowing us to multiply to achieve the final result. 

Example 2: Kilograms to Grams

Conversion: 1000 g = 1 kg

Conversion Factor: 1000g/1kg or 1kg/1000g

Question: Convert 3 kilograms to grams.
Process: 3 kg × (1000g/1kg)= 3000 g

Example 3: Miles to Kilometers

Conversion: 1.60934 km = 1 mi

Question: Convert 4 miles to kilometers.
Process: We start with the given 4 miles and multiply it by its conversion factor. Since we want to cancel out miles, we position miles in the denominator. 

4 mi ×(1.60934 km/1 mi) = 6.43736 km


Example 4: Milliliters to Liters

Conversion: 1 L = 1000 mL

Question: Convert 2500 milliliters to liters.
Process: 2500 ml × (1L/1000 mL)=2.5 L


Example 5: Hours to Seconds

Conversion: 60 min = 1 hr

Conversion: 60 sec = 1 min

Question: Convert 2 hours to seconds.
Process: We start from the given 2 hr. Then we multiply the conversion factor for minutes and then minutes to seconds since our final unit has to be seconds:

2 hr × (60 min/1 hr ) = 120 m × (60 sec/1 min) = 7200 sec

Conclusion

By always setting up the conversion factor with the desired unit in the numerator and the current unit in the denominator, you ensure that you will always multiply. This method simplifies conversions by making the process consistent, avoiding confusion about multiplying or dividing. This approach also helps maintain dimensional accuracy by ensuring that units cancel out correctly during the calculation.